Rule of thumb · Physics SimulationNº 36 / 149

Hohmann is the cheapest transfer — until the ratio passes about 12

Two burns on opposite sides of an ellipse is the minimum-energy route between circular orbits, and LEO to geostationary costs about 3.9 km/s over five and a quarter hours. Past a radius ratio of roughly 11.94, a three-burn bi-elliptic route out to a distant apoapsis is genuinely cheaper.

Why it works

Both burns in a Hohmann transfer fight the same trade: raising apoapsis is cheap deep in the well, circularising at the top is not. Going far higher first makes the second burn almost free, because a spacecraft crawling at apoapsis needs very little push to change its orbit — and past about a twelvefold ratio that saving beats the cost of going out there. The price is time: the bi-elliptic route can take years where Hohmann takes days.

When it fails

"Minimum energy" is not "minimum time" — Hohmann is already the slow option, and bi-elliptic is far slower still. Both assume impulsive burns, coplanar circular orbits and a single dominant body; a plane change, a real finite burn, or a third body makes the neat answer an estimate.

Do it exactly

Estimate with the rule, then check it against the calculator that models it properly.

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What is the most fuel-efficient orbit transfer?

Two burns on opposite sides of an ellipse is the minimum-energy route between circular orbits, and LEO to geostationary costs about 3.9 km/s over five and a quarter hours. Past a radius ratio of roughly 11.94, a three-burn bi-elliptic route out to a distant apoapsis is genuinely cheaper. Both burns in a Hohmann transfer fight the same trade: raising apoapsis is cheap deep in the well, circularising at the top is not.

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