Engineering · structures

Column Buckling Calculator

Euler's formula for slender columns, Johnson's for short ones.
Pcr = π²EI / (KL)²
λ 240 · Euler

Material

Cross-section

Column

Critical stress vs. slenderness

Euler (long column)

Watch it load — and buckle

P = 0% of Pcr
speed
Buckling result
Detail
Field notes

Long, short, or in between

How it works

Two formulas meet in the middle

A slender column fails by suddenly bowing sideways — elastic buckling — governed by Euler's formula, Pcr = π²EI/(KL)², which depends only on stiffness (EI) and geometry, not material strength at all. A short, stocky column instead simply crushes at its yield stress before it ever has a chance to bow. Real columns of intermediate slenderness fail somewhere between those two extremes, which is exactly what Johnson's parabolic formula models — and the two formulas are constructed to meet exactly at the critical slenderness ratio, so this tool automatically picks whichever one actually applies to your column.

Worked example

A 50 mm diameter, 3 m steel column, pinned at both ends, has a slenderness ratio of 240 — well into the Euler regime — giving a critical load of about 67 kN. Fix both ends instead of pinning them and the same column can carry exactly that load, since fixed ends quarter the effective length in the formula.

Why doesn't Euler's formula use yield strength at all?

Because elastic buckling happens before the material ever reaches its yield point — a slender column fails by suddenly deflecting sideways under a load its material could easily survive in pure compression, which is exactly why buckling is a stiffness problem, not a strength problem.

Why does the effective length factor K matter so much?

It appears squared in the denominator, so halving the effective length (say, by fixing rather than pinning an end) quadruples the critical load — end conditions can matter as much as the material or the cross-section itself.

What's radius of gyration, intuitively?

A single number, r = √(I/A), that captures how efficiently a cross-section's material is spread away from its centroid — the same area arranged into a wide, thin shape (like a tube) has a much larger r, and therefore resists buckling far better, than a solid compact shape of equal area.

Why use a hollow tube instead of a solid rod?

For a given amount of material (area), pushing that material further from the centreline dramatically increases I and therefore buckling resistance — a hollow tube can carry a far higher critical load than a solid rod of the same weight, which is exactly why so many structural columns are tubular.

Ideal, centred axial load only. Real columns have imperfections, eccentric loading and residual stress that reduce the true buckling load below this idealised value — always apply a safety factor.